What is the answer to |x^2-9|=|3-4x|+9 ?

The answer to |x^2-9|=|3-4x|+9 is x=-7\lor x=2+sqrt(19)

Solve for x: |x^2-9|=|3-4x|+9

The solution is x=-7\lor x=2+sqrt(19)

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x^{2} - 9 = ∣ 3 - 4 x ∣ + 9

x = - 7 or x = 2 + 19

Decimal Notation

x = - 7, x = 6.35889 \dots

Solution steps

x^{2} - 9 = ∣ 3 - 4 x ∣ + 9

Find positive and negative intervals

x \leq - 3, - 3 < x \leq \frac{3}{4}, \frac{3}{4} < x < 3, x \geq 3

Solve the inequality for each interval

x = - 7 or No Solution or x = 2 + 19

x = - 7 or x = 2 + 19

∣ x - 1 ∣ = ∣ 2 x - 1 ∣

∣ x - 2 ∣ + ∣ x - 6 ∣ = 2

x^{2} + x + 1 = x^{2} + x + 2

∣ x - 6 ∣ + ∣ x - 3 ∣ = 1

∣ x - 3 ∣ - ∣ x - 5 ∣ = 2

What is the answer to |x^2-9|=|3-4x|+9 ?
The answer to |x^2-9|=|3-4x|+9 is x=-7\lor x=2+sqrt(19)
Solve for x: |x^2-9|=|3-4x|+9
The solution is x=-7\lor x=2+sqrt(19)