What are the solutions to the equation 16x^2-24x+9=0 ?

The solutions to the equation 16x^2-24x+9=0 are x= 3/4

Find the zeros of 16x^2-24x+9=0

The zeros of 16x^2-24x+9=0 are x= 3/4

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16 x^{2} - 24 x + 9 = 0

x = \frac{3}{4}

Decimal Notation

x = 0.75

Solution steps

16 x^{2} - 24 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 16 \cdot 9}{2 \cdot 16}

(- 24)^{2} - 4 \cdot 16 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 24 ) \pm 0}{2 \cdot 16}

x = \frac{- ( - 24 )}{2 \cdot 16}

\frac{- ( - 24 )}{2 \cdot 16} = \frac{3}{4}

x = \frac{3}{4}

The solution to the quadratic equation is:

x = \frac{3}{4}

6 x^{2} + 6 x - 72

20 p^{2} - 16 p^{2} q^{2}

- 8 x + (4 + 3 x) = 10 - x

(2 - i) (- 3 + 2 i)

[x - 2] > - 5

What are the solutions to the equation 16x^2-24x+9=0 ?
The solutions to the equation 16x^2-24x+9=0 are x= 3/4
Find the zeros of 16x^2-24x+9=0
The zeros of 16x^2-24x+9=0 are x= 3/4