What is the answer to |x^2-6x+7|=((5x-9))/3 ?

The answer to |x^2-6x+7|=((5x-9))/3 is x=3\lor x=6

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|x^2-6x+7|=((5x-9))/3

x^{2} - 6 x + 7 = \frac{( 5 x - 9 )}{3}

x = 3 or x = 6

Solution steps

x^{2} - 6 x + 7 = \frac{5 x - 9}{3}

Find positive and negative intervals

x \leq - 2 + 3, - 2 + 3 < x < 2 + 3, x \geq 2 + 3

Solve the inequality for each interval

No Solution or x = 3 or x = 6

x = 3 or x = 6

∣ 2 x + 5 ∣ + ∣ 3 - 7 x ∣ = 16

∣ x ∣^{2} - ∣ x ∣ + 4 = 2 x^{2} - 3 ∣ x ∣ + 1

∣ x ∣ + 2 ∣ x - 1 ∣ - 3 ∣ x - 2 ∣ = 4

11 + 5 ∣ x - 1 ∣ = 17

∣ x - 3 ∣ + ∣ x + 2 ∣ - ∣ x - 4 ∣ = 3

What is the answer to |x^2-6x+7|=((5x-9))/3 ?
The answer to |x^2-6x+7|=((5x-9))/3 is x=3\lor x=6
Solve for x: |x^2-6x+7|=((5x-9))/3
The solution is x=3\lor x=6