What is the answer to (3x-2)^2-5|3x-2|-6=0 ?

The answer to (3x-2)^2-5|3x-2|-6=0 is x=-4/3 \lor x= 8/3

Solve for x: (3x-2)^2-5|3x-2|-6=0

The solution is x=-4/3 \lor x= 8/3

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(3 x - 2)^{2} - 5 ∣ 3 x - 2 ∣ - 6 = 0

x = - \frac{4}{3} or x = \frac{8}{3}

Decimal Notation

x = - 1.33333 \dots, x = 2.66666 \dots

Solution steps

(3 x - 2)^{2} - 5 ∣ 3 x - 2 ∣ - 6 = 0

Find positive and negative intervals

x < \frac{2}{3}, x \geq \frac{2}{3}

Solve the inequality for each interval

x = - \frac{4}{3} or x = \frac{8}{3}

x^{2} - 3 x + 2 = ∣ 2 x - 3 ∣

7 (∣ x ∣ + 6) = 7 (∣ x ∣ + 5)

3 x^{2} - 4 x + 2 = 5 x - 4

∣ 2 x - 1 ∣ + ∣ 2 x + 3 ∣ = 6

∣ 3 x - 8 ∣ + ∣ 3 x + 1 ∣ + ∣ 3 x + 5 ∣ = 21

What is the answer to (3x-2)^2-5|3x-2|-6=0 ?
The answer to (3x-2)^2-5|3x-2|-6=0 is x=-4/3 \lor x= 8/3
Solve for x: (3x-2)^2-5|3x-2|-6=0
The solution is x=-4/3 \lor x= 8/3