What is the answer to |x^2-4x+3|=3|x^2-5x+4| ?

The answer to |x^2-4x+3|=3|x^2-5x+4| is x=1\lor x= 15/4 \lor x= 9/2

Solve for x: |x^2-4x+3|=3|x^2-5x+4|

The solution is x=1\lor x= 15/4 \lor x= 9/2

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x^{2} - 4 x + 3 = 3 x^{2} - 5 x + 4

x = 1 or x = \frac{15}{4} or x = \frac{9}{2}

Solution steps

x^{2} - 4 x + 3 = 3 x^{2} - 5 x + 4

Find positive and negative intervals

x \leq 1, 1 < x < 3, 3 \leq x < 4, x \geq 4

Solve the inequality for each interval

x = 1 or No Solution or x = \frac{15}{4} or x = \frac{9}{2}

x = 1 or x = \frac{15}{4} or x = \frac{9}{2}

2 + 3 ∣ 2 x + 1 ∣ = 4

∣ x - 1 ∣ - ∣ x - 2 ∣ = 10

x^{2} + 3 ∣ x ∣ + 2 = 0

∣ x - 3 ∣ = x - 3

2 ∣ x - 2 ∣ - 3 ∣ x + 4 ∣ = 1

What is the answer to |x^2-4x+3|=3|x^2-5x+4| ?
The answer to |x^2-4x+3|=3|x^2-5x+4| is x=1\lor x= 15/4 \lor x= 9/2
Solve for x: |x^2-4x+3|=3|x^2-5x+4|
The solution is x=1\lor x= 15/4 \lor x= 9/2