What is the answer to |x^2-1|-2x=1 ?

The answer to |x^2-1|-2x=1 is x=0\lor x=1+sqrt(3)

Solve for x: |x^2-1|-2x=1

The solution is x=0\lor x=1+sqrt(3)

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x^{2} - 1 - 2 x = 1

x = 0 or x = 1 + 3

Decimal Notation

x = 0, x = 2.73205 \dots

Solution steps

x^{2} - 1 - 2 x = 1

Find positive and negative intervals

x \leq - 1, - 1 < x < 1, x \geq 1

Solve the inequality for each interval

No Solution or x = 0 or x = 1 + 3

x = 0 or x = 1 + 3

∣ 5 x - 6 ∣ = x^{2}

1 + ∣ x ∣ = ∣ x + 1 ∣

∣ x - 1 ∣ + ∣ x - 2 ∣ + ∣ x - 3 ∣ = 2

∣ x - 1 ∣ + ∣ x - 2 ∣ + ∣ x - 3 ∣ = 6

x^{2} + x + 1 - x^{2} - x - 1 = 0

What is the answer to |x^2-1|-2x=1 ?
The answer to |x^2-1|-2x=1 is x=0\lor x=1+sqrt(3)
Solve for x: |x^2-1|-2x=1
The solution is x=0\lor x=1+sqrt(3)