What is the answer to 3x-|1-x|=|x+3|-3|2-x| ?

The answer to 3x-|1-x|=|x+3|-3|2-x| is x=-4\lor x=2

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3x-|1-x|=|x+3|-3|2-x|

3 x - ∣ 1 - x ∣ = ∣ x + 3 ∣ - 3 ∣ 2 - x ∣

x = - 4 or x = 2

Solution steps

3 x - ∣ 1 - x ∣ = ∣ x + 3 ∣ - 3 ∣ 2 - x ∣

Find positive and negative intervals

x < - 3, - 3 \leq x \leq 1, 1 < x \leq 2, x > 2

Solve the inequality for each interval

x = - 4 or No Solution or x = 2

x = - 4 or x = 2

∣ x + 2 ∣ = 2 ∣ x + 1 ∣

∣ 2 x + 3 ∣ = ∣ 7 - x ∣

∣ x - 2 ∣ - ∣ x - 6 ∣ = 1

∣ 2 x - 3 ∣ = ∣ x + 7 ∣

- x^{2} + 4 x - 7 - x^{2} + 4 x - 7 = 0

What is the answer to 3x-|1-x|=|x+3|-3|2-x| ?
The answer to 3x-|1-x|=|x+3|-3|2-x| is x=-4\lor x=2
Solve for x: 3x-|1-x|=|x+3|-3|2-x|
The solution is x=-4\lor x=2