What are the solutions to the equation x^2+2+3x=0 ?

The solutions to the equation x^2+2+3x=0 are x=-1,x=-2

Find the zeros of x^2+2+3x=0

The zeros of x^2+2+3x=0 are x=-1,x=-2

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x^{2} + 2 + 3 x = 0

x = - 1, x = - 2

Solution steps

x^{2} + 2 + 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 2 = 1

x_{1, 2} = \frac{- 3 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 1}{2 \cdot 1}, x_{2} = \frac{- 3 - 1}{2 \cdot 1}

x = \frac{- 3 + 1}{2 \cdot 1} : - 1

x = \frac{- 3 - 1}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = - 1, x = - 2

- (\frac{5}{4})^{0}

4 x (3 x - 1) = 1

\frac{( 6 - 7 i )}{( 4 - 5 i )}

x^{2} - 30 - x = 0

What are the solutions to the equation x^2+2+3x=0 ?
The solutions to the equation x^2+2+3x=0 are x=-1,x=-2
Find the zeros of x^2+2+3x=0
The zeros of x^2+2+3x=0 are x=-1,x=-2