What is the answer to solvefor x,3|y-2|+5(2x-y+1)^2=0 ?

The answer to solvefor x,3|y-2|+5(2x-y+1)^2=0 is No Solution for x\in\mathbb{R}

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solvefor x,3|y-2|+5(2x-y+1)^2=0

solve for

x, 3 ∣ y - 2 ∣ + 5 (2 x - y + 1)^{2} = 0

No Solution for x \in R

Solution steps

3 ∣ y - 2 ∣ + 5 (2 x - y + 1)^{2} = 0

Find positive and negative intervals

x < 2, x \geq 2

Solve the inequality for each interval

No Solution for x \in R

3 ∣ x ∣ + 2 = 8

x^{2} - 3 x + 2 = 2

∣ 2 x - 1 ∣ = ∣ x - 3 ∣

∣ x + 1 ∣ + ∣ x - 2 ∣ = 2

\frac{∣ x - 5 ∣ - 1}{2} = \frac{1}{2}

What is the answer to solvefor x,3|y-2|+5(2x-y+1)^2=0 ?
The answer to solvefor x,3|y-2|+5(2x-y+1)^2=0 is No Solution for x\in\mathbb{R}