What is the answer to |x^2-2x-8|+|x^2+x-2|=3|x+2| ?

The answer to |x^2-2x-8|+|x^2+x-2|=3|x+2| is x=-2\lor 1<= x<= 4

Solve for x: |x^2-2x-8|+|x^2+x-2|=3|x+2|

The solution is x=-2\lor 1<= x<= 4

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The solution is x=-2\lor 1<= x<= 4

x^{2} - 2 x - 8 + x^{2} + x - 2 = 3 ∣ x + 2 ∣

x = - 2 or 1 \leq x \leq 4

Solution steps

x^{2} - 2 x - 8 + x^{2} + x - 2 = 3 ∣ x + 2 ∣

Find positive and negative intervals

x \leq - 2, - 2 < x < 1, 1 \leq x < 4, x \geq 4

Solve the inequality for each interval

x = - 2 or No Solution or 1 \leq x < 4 or x = 4

Merge Overlapping Intervals

x = - 2 or 1 \leq x \leq 4

∣ - 3 x + 2 ∣ = 4

∣ x ∣ = 2 x - 3

- ∣ - 2 + (- a) ∣ + 90 = - 7

x^{2} - 6 x - ∣ 5 x - 15 ∣ - 5 = 0

∣ x + 8 ∣ = 3.5

What is the answer to |x^2-2x-8|+|x^2+x-2|=3|x+2| ?
The answer to |x^2-2x-8|+|x^2+x-2|=3|x+2| is x=-2\lor 1<= x<= 4
Solve for x: |x^2-2x-8|+|x^2+x-2|=3|x+2|
The solution is x=-2\lor 1<= x<= 4