What is the answer to |x-2|+|x|=|x^2-2x| ?

The answer to |x-2|+|x|=|x^2-2x| is x=-sqrt(2)\lor x=2+sqrt(2)

Solve for x: |x-2|+|x|=|x^2-2x|

The solution is x=-sqrt(2)\lor x=2+sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

∣ x - 2 ∣ + ∣ x ∣ = x^{2} - 2 x

x = - 2 or x = 2 + 2

Decimal Notation

x = - 1.41421 \dots, x = 3.41421 \dots

Solution steps

∣ x - 2 ∣ + ∣ x ∣ = x^{2} - 2 x

Find positive and negative intervals

x \leq 0, 0 < x < 2, x \geq 2

Solve the inequality for each interval

x = - 2 or No Solution or x = 2 + 2

x = - 2 or x = 2 + 2

x + 2 = 3

∣ x - 1 ∣ + ∣ x - 2 ∣ = 5

∣ 3 x + 2 ∣ = ∣ x - 1 ∣

∣ x - 1 ∣ + ∣ 4 - x ∣ = 6

x^{2} - 5 ∣ x - 1 ∣ - 1 = 0

What is the answer to |x-2|+|x|=|x^2-2x| ?
The answer to |x-2|+|x|=|x^2-2x| is x=-sqrt(2)\lor x=2+sqrt(2)
Solve for x: |x-2|+|x|=|x^2-2x|
The solution is x=-sqrt(2)\lor x=2+sqrt(2)