What is the answer to |x^2+x-5|=|4x-1| ?

The answer to |x^2+x-5|=|4x-1| is x=-6\lor x=-1\lor x=1\lor x=4

Solve for x: |x^2+x-5|=|4x-1|

The solution is x=-6\lor x=-1\lor x=1\lor x=4

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x^{2} + x - 5 = ∣ 4 x - 1 ∣

x = - 6 or x = - 1 or x = 1 or x = 4

Solution steps

x^{2} + x - 5 = ∣ 4 x - 1 ∣

Find positive and negative intervals

x \leq \frac{- 21 - 1}{2}, \frac{- 21 - 1}{2} < x < \frac{1}{4}, \frac{1}{4} \leq x < \frac{21 - 1}{2}, x \geq \frac{21 - 1}{2}

Solve the inequality for each interval

x = - 6 or x = - 1 or x = 1 or x = 4

∣ x - 2 ∣ = x^{2}

(x^{2} + x + 2) + ∣ x + 1 ∣ = 5

∣ x - 1 ∣ - ∣ x - 2 ∣ + ∣ x - 3 ∣ = 5 x - 1

\frac{( 3 x + 4 )}{3} = 7

∣ x - 4 ∣ + ∣ x - 7 ∣ = 11

What is the answer to |x^2+x-5|=|4x-1| ?
The answer to |x^2+x-5|=|4x-1| is x=-6\lor x=-1\lor x=1\lor x=4
Solve for x: |x^2+x-5|=|4x-1|
The solution is x=-6\lor x=-1\lor x=1\lor x=4