What is the answer to (x+3)|x+2|+|2x+3|+1=0 ?

The answer to (x+3)|x+2|+|2x+3|+1=0 is x=-(7+sqrt(17))/2

Solve for x: (x+3)|x+2|+|2x+3|+1=0

The solution is x=-(7+sqrt(17))/2

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(x + 3) ∣ x + 2 ∣ + ∣ 2 x + 3 ∣ + 1 = 0

x = - \frac{7 + 17}{2}

Solution steps

(x + 3) ∣ x + 2 ∣ + ∣ 2 x + 3 ∣ + 1 = 0

Find positive and negative intervals

x < - 2, - 2 \leq x < - \frac{3}{2}, x \geq - \frac{3}{2}

Solve the inequality for each interval

x = - \frac{7 + 17}{2} or No Solution

x = - \frac{7 + 17}{2}

∣ x - 2 ∣ + ∣ x - 4 ∣ = 5

13 + ∣ x ∣ = ∣ - 6 ∣ + 17

∣ - x ∣ = 5

∣ x + 1 ∣ = ∣ 2 x - 1 ∣

3 ∣ x + 1 ∣ = 5 - 2 x

What is the answer to (x+3)|x+2|+|2x+3|+1=0 ?
The answer to (x+3)|x+2|+|2x+3|+1=0 is x=-(7+sqrt(17))/2
Solve for x: (x+3)|x+2|+|2x+3|+1=0
The solution is x=-(7+sqrt(17))/2