What is the answer to |x^2-4x+7|=|2x^2-3x+5| ?

The answer to |x^2-4x+7|=|2x^2-3x+5| is x=-2\lor x=1

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|x^2-4x+7|=|2x^2-3x+5|

x^{2} - 4 x + 7 = 2 x^{2} - 3 x + 5

x = - 2 or x = 1

Solution steps

x^{2} - 4 x + 7 = 2 x^{2} - 3 x + 5

Find positive and negative intervals

- \infty < x < \infty

Solve the inequality for each interval

(x = - 2 or x = 1)

x = - 2 or x = 1

∣ 10 x + 9 ∣ = 18

x^{2} - 4 x = - 5

∣ x + 1 ∣ + ∣ x - 2 ∣ + ∣ x - 5 ∣ = x + 4

x^{2} - 2 = 2 - 3 x

12 + 3 ∣ x + 3 ∣ = 9 x - 9

What is the answer to |x^2-4x+7|=|2x^2-3x+5| ?
The answer to |x^2-4x+7|=|2x^2-3x+5| is x=-2\lor x=1
Solve for x: |x^2-4x+7|=|2x^2-3x+5|
The solution is x=-2\lor x=1