What is the answer to |x^2+2x+3|=x^2-x+1 ?

The answer to |x^2+2x+3|=x^2-x+1 is x=-2/3

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|x^2+2x+3|=x^2-x+1

x^{2} + 2 x + 3 = x^{2} - x + 1

x = - \frac{2}{3}

Solution steps

x^{2} + 2 x + 3 = x^{2} - x + 1

Find positive and negative intervals

- \infty < x < \infty

Solve the inequality for each interval

x = - \frac{2}{3}

5 - 6 ∣ x ∣ = - 7

16 - x^{2} = 20

∣ x - 3 ∣ + ∣ x - 4 ∣ = 3

∣ x + 3 ∣ + ∣ x ∣ = 7

f, ∣ f ∣ = 2

What is the answer to |x^2+2x+3|=x^2-x+1 ?
The answer to |x^2+2x+3|=x^2-x+1 is x=-2/3
Solve for x: |x^2+2x+3|=x^2-x+1
The solution is x=-2/3