What is the answer to |x^2-1|=|2x-1| ?

The answer to |x^2-1|=|2x-1| is x=-1-sqrt(3)\lor x=0\lor x=sqrt(3)-1\lor x=2

Solve for x: |x^2-1|=|2x-1|

The solution is x=-1-sqrt(3)\lor x=0\lor x=sqrt(3)-1\lor x=2

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x^{2} - 1 = ∣ 2 x - 1 ∣

x = - 1 - 3 or x = 0 or x = 3 - 1 or x = 2

Solution steps

x^{2} - 1 = ∣ 2 x - 1 ∣

Find positive and negative intervals

x \leq - 1, - 1 < x < \frac{1}{2}, \frac{1}{2} \leq x < 1, x \geq 1

Solve the inequality for each interval

x = - 1 - 3 or x = 0 or x = 3 - 1 or x = 2

∣ 2 - 3 x ∣ - x = 0

∣ 15 x - 7 ∣ - ∣ 5 x + 3 ∣ = 0

∣ 4 x + 7 ∣ - 3 = 21

∣ 3 x - 1 ∣ = x

∣ x + 2 ∣ - 7 = 1

What is the answer to |x^2-1|=|2x-1| ?
The answer to |x^2-1|=|2x-1| is x=-1-sqrt(3)\lor x=0\lor x=sqrt(3)-1\lor x=2
Solve for x: |x^2-1|=|2x-1|
The solution is x=-1-sqrt(3)\lor x=0\lor x=sqrt(3)-1\lor x=2