What is the answer to |x^2-4x-20|=1 ?

The answer to |x^2-4x-20|=1 is x=-3\lor x=2-sqrt(23)\lor x=2+sqrt(23)\lor x=7

Solve for x: |x^2-4x-20|=1

The solution is x=-3\lor x=2-sqrt(23)\lor x=2+sqrt(23)\lor x=7

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x^{2} - 4 x - 20 = 1

x = - 3 or x = 2 - 23 or x = 2 + 23 or x = 7

Decimal Notation

x = - 3, x = - 2.79583 \dots, x = 6.79583 \dots, x = 7

Solution steps

x^{2} - 4 x - 20 = 1

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 4 x - 20 = - 1 or x^{2} - 4 x - 20 = 1

x^{2} - 4 x - 20 = - 1 or x^{2} - 4 x - 20 = 1

(x = 2 - 23 or x = 2 + 23) or (x = - 3 or x = 7)

x = - 3 or x = 2 - 23 or x = 2 + 23 or x = 7

∣ 2 x + 1 ∣ - 2 ∣ x - 2 ∣ = 5

∣ x - 1 ∣ + ∣ x - 4 ∣ = 3

∣ 2 x ∣ + ∣ x - 5 ∣ = 8

6 \frac{( 4 w - 1 )}{6} = \frac{( 2 w )}{3} + \frac{1}{4}

(x - 1 - x^{2})^{3} + x^{2} - x + 1 = 0

What is the answer to |x^2-4x-20|=1 ?
The answer to |x^2-4x-20|=1 is x=-3\lor x=2-sqrt(23)\lor x=2+sqrt(23)\lor x=7
Solve for x: |x^2-4x-20|=1
The solution is x=-3\lor x=2-sqrt(23)\lor x=2+sqrt(23)\lor x=7