What is the answer to |-x^2+x-1|=|x+5| ?

The answer to |-x^2+x-1|=|x+5| is x=1-sqrt(5)\lor x=1+sqrt(5)

Solve for x: |-x^2+x-1|=|x+5|

The solution is x=1-sqrt(5)\lor x=1+sqrt(5)

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- x^{2} + x - 1 = ∣ x + 5 ∣

x = 1 - 5 or x = 1 + 5

Decimal Notation

x = - 1.23606 \dots, x = 3.23606 \dots

Solution steps

- x^{2} + x - 1 = ∣ x + 5 ∣

Find positive and negative intervals

x < - 5, x \geq - 5

Solve the inequality for each interval

No Solution or (x = 1 - 5 or x = 1 + 5)

x = 1 - 5 or x = 1 + 5

∣ n ∣ + ∣ n - 4 ∣ + ∣ n - 6 ∣ = 10

∣ x ∣ + ∣ x + 5 ∣ = 5

∣ x - 8 ∣ = 3 x^{2} - 5 - ∣ 2 x + 3 ∣

3 ∣ x + 2 ∣ - x = 3

∣ x - 5 ∣^{2} + ∣ x - 5 ∣ - 24 = 0

What is the answer to |-x^2+x-1|=|x+5| ?
The answer to |-x^2+x-1|=|x+5| is x=1-sqrt(5)\lor x=1+sqrt(5)
Solve for x: |-x^2+x-1|=|x+5|
The solution is x=1-sqrt(5)\lor x=1+sqrt(5)