What is the answer to |x-2|+|x-3|+|x+1|=7 ?

The answer to |x-2|+|x-3|+|x+1|=7 is x=-1\lor x= 11/3

Solve for x: |x-2|+|x-3|+|x+1|=7

The solution is x=-1\lor x= 11/3

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∣ x - 2 ∣ + ∣ x - 3 ∣ + ∣ x + 1 ∣ = 7

x = - 1 or x = \frac{11}{3}

Decimal Notation

x = - 1, x = 3.66666 \dots

Solution steps

∣ x - 2 ∣ + ∣ x - 3 ∣ + ∣ x + 1 ∣ = 7

Find positive and negative intervals

x < - 1, - 1 \leq x < 2, 2 \leq x < 3, x \geq 3

Solve the inequality for each interval

No Solution or x = - 1 or x = \frac{11}{3}

x = - 1 or x = \frac{11}{3}

∣ 3 x - 5 ∣ - ∣ 1 - x ∣ = 0

∣ x + 2 ∣ + ∣ x + 3 ∣ = x

∣ x - 2 ∣ + ∣ 2 x - 3 ∣ + ∣ 3 x - 8 ∣ = 18

∣ x ∣ + 4 = 10

∣ 2 x - 6 ∣ + ∣ x - y + 3 ∣ = 0

What is the answer to |x-2|+|x-3|+|x+1|=7 ?
The answer to |x-2|+|x-3|+|x+1|=7 is x=-1\lor x= 11/3
Solve for x: |x-2|+|x-3|+|x+1|=7
The solution is x=-1\lor x= 11/3