What is the answer to |2x^2-4|=|x^2| ?

The answer to |2x^2-4|=|x^2| is x=-2\lor x=-2/(sqrt(3))\lor x= 2/(sqrt(3))\lor x=2

Solve for x: |2x^2-4|=|x^2|

The solution is x=-2\lor x=-2/(sqrt(3))\lor x= 2/(sqrt(3))\lor x=2

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2 x^{2} - 4 = x^{2}

x = - 2 or x = - \frac{2}{3} or x = \frac{2}{3} or x = 2

Decimal Notation

x = - 2, x = - 1.15470 \dots, x = 1.15470 \dots, x = 2

Solution steps

2 x^{2} - 4 = x^{2}

Find positive and negative intervals

x \leq - 2, - 2 < x < 2, x \geq 2

Solve the inequality for each interval

x = - 2 or (x = - \frac{2}{3} or x = \frac{2}{3}) or x = 2

x = - 2 or x = - \frac{2}{3} or x = \frac{2}{3} or x = 2

∣ a ∣ = 2, ∣ b ∣ = 3, ∣ 3 a + b ∣ = 7

x + \frac{5}{6} = \frac{1}{5} - \frac{2}{3} + \frac{( - 3 )}{4}

∣ 2 x - 1 ∣ = 3 - 2 x

∣ x - 1 ∣ + ∣ x - 2 ∣ + ∣ x - 3 ∣ = 4

[x^{2} - 2] = 4

What is the answer to |2x^2-4|=|x^2| ?
The answer to |2x^2-4|=|x^2| is x=-2\lor x=-2/(sqrt(3))\lor x= 2/(sqrt(3))\lor x=2
Solve for x: |2x^2-4|=|x^2|
The solution is x=-2\lor x=-2/(sqrt(3))\lor x= 2/(sqrt(3))\lor x=2