What are the solutions to the equation 7x^2-19x+10=0 ?

The solutions to the equation 7x^2-19x+10=0 are x=2,x= 5/7

Find the zeros of 7x^2-19x+10=0

The zeros of 7x^2-19x+10=0 are x=2,x= 5/7

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7 x^{2} - 19 x + 10 = 0

x = 2, x = \frac{5}{7}

Solution steps

7 x^{2} - 19 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 7 \cdot 10}{2 \cdot 7}

(- 19)^{2} - 4 \cdot 7 \cdot 10 = 9

x_{1, 2} = \frac{- ( - 19 ) \pm 9}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 9}{2 \cdot 7}, x_{2} = \frac{- ( - 19 ) - 9}{2 \cdot 7}

x = \frac{- ( - 19 ) + 9}{2 \cdot 7} : 2

x = \frac{- ( - 19 ) - 9}{2 \cdot 7} : \frac{5}{7}

The solutions to the quadratic equation are:

x = 2, x = \frac{5}{7}

2. 5^{3}

10 (p + 1) = 16 (p + 10)

150 d^{2} - 3.15 d - 16.19 = 0

125 (x + 2)^{3} + 64 (x - 5)^{3}

(\frac{1}{4})^{x}

What are the solutions to the equation 7x^2-19x+10=0 ?
The solutions to the equation 7x^2-19x+10=0 are x=2,x= 5/7
Find the zeros of 7x^2-19x+10=0
The zeros of 7x^2-19x+10=0 are x=2,x= 5/7