What is the answer to |x^2-x-12|=x+12-x^2 ?

The answer to |x^2-x-12|=x+12-x^2 is -3<= x<= 4

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|x^2-x-12|=x+12-x^2

x^{2} - x - 12 = x + 12 - x^{2}

- 3 \leq x \leq 4

Solution steps

x^{2} - x - 12 = x + 12 - x^{2}

Find positive and negative intervals

x \leq - 3, - 3 < x < 4, x \geq 4

Solve the inequality for each interval

x = - 3 or - 3 < x < 4 or x = 4

Merge Overlapping Intervals

- 3 \leq x \leq 4

∣ 6 x + 9 ∣ = ∣ 3 x - 7 ∣

∣ 3 x - 4 ∣ = ∣ x ∣

2 x^{2} + 5 + ∣ 2 x - 6 ∣ = 8

5 - ∣ 2 x + 1 ∣ = 0

∣ x + 1 ∣ + ∣ 2 x + 4 ∣ = 5

What is the answer to |x^2-x-12|=x+12-x^2 ?
The answer to |x^2-x-12|=x+12-x^2 is -3<= x<= 4
Solve for x: |x^2-x-12|=x+12-x^2
The solution is -3<= x<= 4