What is the answer to |x^2-4|=-x^2+4 ?

The answer to |x^2-4|=-x^2+4 is -2<= x<= 2

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|x^2-4|=-x^2+4

x^{2} - 4 = - x^{2} + 4

- 2 \leq x \leq 2

Solution steps

x^{2} - 4 = - x^{2} + 4

Find positive and negative intervals

x \leq - 2, - 2 < x < 2, x \geq 2

Solve the inequality for each interval

x = - 2 or - 2 < x < 2 or x = 2

Merge Overlapping Intervals

- 2 \leq x \leq 2

∣ 2 + x ∣ = ∣ x - 8 ∣

∣ 3 x + 1 ∣ = x - 2

\frac{( x - 3 )}{4}^{2} = \frac{9}{4}

4 x (x - 3) - 5 ∣ 2 x - 3 ∣ + 13 = 0

∣ x ∣ = x + 2

What is the answer to |x^2-4|=-x^2+4 ?
The answer to |x^2-4|=-x^2+4 is -2<= x<= 2
Solve for x: |x^2-4|=-x^2+4
The solution is -2<= x<= 2