What is the answer to |x^2+x+1|=5 ?

The answer to |x^2+x+1|=5 is x=(-1-sqrt(17))/2 \lor x=(-1+sqrt(17))/2

Solve for x: |x^2+x+1|=5

The solution is x=(-1-sqrt(17))/2 \lor x=(-1+sqrt(17))/2

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x^{2} + x + 1 = 5

x = \frac{- 1 - 17}{2} or x = \frac{- 1 + 17}{2}

Decimal Notation

x = - 2.56155 \dots, x = 1.56155 \dots

Solution steps

x^{2} + x + 1 = 5

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + x + 1 = - 5 or x^{2} + x + 1 = 5

x^{2} + x + 1 = - 5 or x^{2} + x + 1 = 5

No Solution or (x = \frac{- 1 - 17}{2} or x = \frac{- 1 + 17}{2})

x = \frac{- 1 - 17}{2} or x = \frac{- 1 + 17}{2}

\frac{x - \frac{2}{5} - 1}{6} = (- \frac{2}{3})^{0}

x, x y = ∣ x - 5 ∣ - 8

∣ x - 1 ∣ + ∣ x - 7 ∣ = 5

∣ x - 1 ∣ + ∣ x - 7 ∣ = 6

∣ 2 x - 3 ∣ = x - 3

What is the answer to |x^2+x+1|=5 ?
The answer to |x^2+x+1|=5 is x=(-1-sqrt(17))/2 \lor x=(-1+sqrt(17))/2
Solve for x: |x^2+x+1|=5
The solution is x=(-1-sqrt(17))/2 \lor x=(-1+sqrt(17))/2