What is the answer to |2x-3|+|4-x|=|x+1| ?

The answer to |2x-3|+|4-x|=|x+1| is 3/2 <= x<= 4

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|2x-3|+|4-x|=|x+1|

∣ 2 x - 3 ∣ + ∣ 4 - x ∣ = ∣ x + 1 ∣

\frac{3}{2} \leq x \leq 4

Solution steps

∣ 2 x - 3 ∣ + ∣ 4 - x ∣ = ∣ x + 1 ∣

Find positive and negative intervals

x < - 1, - 1 \leq x < \frac{3}{2}, \frac{3}{2} \leq x \leq 4, x > 4

Solve the inequality for each interval

No Solution or \frac{3}{2} \leq x \leq 4

Merge Overlapping Intervals

\frac{3}{2} \leq x \leq 4

∣ x - 2 ∣ + ∣ x + 6 ∣ = 8

x^{2} + 1 = x^{2} - 3 x

∣ x - 3 ∣ = 4 - x

(3 x - 2) 2 - 5 ∣ 3 x - 2 ∣ - 6 = 0

∣ x - 4 ∣ - ∣ x ∣ = 4

What is the answer to |2x-3|+|4-x|=|x+1| ?
The answer to |2x-3|+|4-x|=|x+1| is 3/2 <= x<= 4
Solve for x: |2x-3|+|4-x|=|x+1|
The solution is 3/2 <= x<= 4