What is the answer to |x^2-x+3|=|x^2-4x+7| ?

The answer to |x^2-x+3|=|x^2-4x+7| is x= 4/3

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|x^2-x+3|=|x^2-4x+7|

x^{2} - x + 3 = x^{2} - 4 x + 7

x = \frac{4}{3}

Decimal Notation

x = 1.33333 \dots

Solution steps

x^{2} - x + 3 = x^{2} - 4 x + 7

Find positive and negative intervals

- \infty < x < \infty

Solve the inequality for each interval

x = \frac{4}{3}

∣ x + 3 ∣ - 5 = 4

∣ x - 1 ∣ + ∣ x - 3 ∣ = \frac{3}{2}

∣ x + 3 ∣ + 3 = 3

4 x^{2} - 1 = 4 x^{2} - 1

∣ x ∣ + ∣ x + 2 ∣ = 4

What is the answer to |x^2-x+3|=|x^2-4x+7| ?
The answer to |x^2-x+3|=|x^2-4x+7| is x= 4/3
Solve for x: |x^2-x+3|=|x^2-4x+7|
The solution is x= 4/3