What is the answer to |x^2-1|+|x|=2 ?

The answer to |x^2-1|+|x|=2 is x=(1-sqrt(13))/2 \lor x=(-1+sqrt(13))/2

Solve for x: |x^2-1|+|x|=2

The solution is x=(1-sqrt(13))/2 \lor x=(-1+sqrt(13))/2

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x^{2} - 1 + ∣ x ∣ = 2

x = \frac{1 - 13}{2} or x = \frac{- 1 + 13}{2}

Decimal Notation

x = - 1.30277 \dots, x = 1.30277 \dots

Solution steps

x^{2} - 1 + ∣ x ∣ = 2

Find positive and negative intervals

x \leq - 1, - 1 < x < 0, 0 \leq x < 1, x \geq 1

Solve the inequality for each interval

x = \frac{1 - 13}{2} or No Solution or x = \frac{- 1 + 13}{2}

x = \frac{1 - 13}{2} or x = \frac{- 1 + 13}{2}

3 - 2 ∣ x + 1 ∣ = 1

(x^{2} + ∣ x - 1 ∣) = x (x + 2)

(d) ∣ x - 3 ∣ + ∣ x + 5 ∣ = 10

∣ x ∣ + ∣ - 2 ∣ = 22

5 + 3 ∣ 2 x - 7 ∣ = 14

What is the answer to |x^2-1|+|x|=2 ?
The answer to |x^2-1|+|x|=2 is x=(1-sqrt(13))/2 \lor x=(-1+sqrt(13))/2
Solve for x: |x^2-1|+|x|=2
The solution is x=(1-sqrt(13))/2 \lor x=(-1+sqrt(13))/2