What is the answer to |x^2-9|=|2x-5|-4 ?

The answer to |x^2-9|=|2x-5|-4 is x=-1-sqrt(11)\lor x=-2

Solve for x: |x^2-9|=|2x-5|-4

The solution is x=-1-sqrt(11)\lor x=-2

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x^{2} - 9 = ∣ 2 x - 5 ∣ - 4

x = - 1 - 11 or x = - 2

Decimal Notation

x = - 4.31662 \dots, x = - 2

Solution steps

x^{2} - 9 = ∣ 2 x - 5 ∣ - 4

Find positive and negative intervals

x \leq - 3, - 3 < x < \frac{5}{2}, \frac{5}{2} \leq x < 3, x \geq 3

Solve the inequality for each interval

x = - 1 - 11 or x = - 2 or No Solution

x = - 1 - 11 or x = - 2

∣ x + 4 ∣^{2} + 5 = 20

∣ 1 - 2 x ∣ = 2 x - 1

∣ 3 x - 1 ∣ + ∣ 2 x - 3 ∣ - 4 = 0

∣ x + 1 ∣ = 10

∣ x - 1 ∣ + ∣ 2 - x ∣ = 3

What is the answer to |x^2-9|=|2x-5|-4 ?
The answer to |x^2-9|=|2x-5|-4 is x=-1-sqrt(11)\lor x=-2
Solve for x: |x^2-9|=|2x-5|-4
The solution is x=-1-sqrt(11)\lor x=-2