What is the answer to (1)|x^2-1|=x+3 ?

The answer to (1)|x^2-1|=x+3 is x=(1-sqrt(17))/2 \lor x=(1+sqrt(17))/2

Solve for x: (1)|x^2-1|=x+3

The solution is x=(1-sqrt(17))/2 \lor x=(1+sqrt(17))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1) x^{2} - 1 = x + 3

x = \frac{1 - 17}{2} or x = \frac{1 + 17}{2}

Decimal Notation

x = - 1.56155 \dots, x = 2.56155 \dots

Solution steps

1 \cdot x^{2} - 1 = x + 3

Find positive and negative intervals

x \leq - 1, - 1 < x < 1, x \geq 1

Solve the inequality for each interval

x = \frac{1 - 17}{2} or No Solution or x = \frac{1 + 17}{2}

x = \frac{1 - 17}{2} or x = \frac{1 + 17}{2}

20 + 5 ∣ 2 x - 1 ∣ + 5 = 20

7 + 3 ∣ 2 x - 3 ∣ = 5

∣ x ∣^{3} - 3 x^{2} + 3 ∣ x ∣ - 2 = 0

∣ x - a ∣ = 2

∣ 3 x + 1 ∣ = ∣ x - 2 ∣

What is the answer to (1)|x^2-1|=x+3 ?
The answer to (1)|x^2-1|=x+3 is x=(1-sqrt(17))/2 \lor x=(1+sqrt(17))/2
Solve for x: (1)|x^2-1|=x+3
The solution is x=(1-sqrt(17))/2 \lor x=(1+sqrt(17))/2