What is the answer to |x^2+x+1|+|2x-3|=4x ?

The answer to |x^2+x+1|+|2x-3|=4x is x=1\lor x=2

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|x^2+x+1|+|2x-3|=4x

x^{2} + x + 1 + ∣ 2 x - 3 ∣ = 4 x

x = 1 or x = 2

Solution steps

x^{2} + x + 1 + ∣ 2 x - 3 ∣ = 4 x

Find positive and negative intervals

x < \frac{3}{2}, x \geq \frac{3}{2}

Solve the inequality for each interval

x = 1 or x = 2

∣ - 13 ∣ + \frac{3 x + 6}{7} + ∣ 4 ∣ = 25

∣ x + 3 ∣ - ∣ 4 - x ∣ = ∣ 8 + x ∣

∣ x - 3 ∣ + ∣ x + 5 ∣ = 8

x^{2} = ∣ x ∣

a = ∣ 2 x - 1 ∣ + 2

What is the answer to |x^2+x+1|+|2x-3|=4x ?
The answer to |x^2+x+1|+|2x-3|=4x is x=1\lor x=2
Solve for x: |x^2+x+1|+|2x-3|=4x
The solution is x=1\lor x=2