What is the answer to |x^2+x+1|=|2x^2+x-1| ?

The answer to |x^2+x+1|=|2x^2+x-1| is x=-sqrt(2)\lor x=-2/3 \lor x=0\lor x=sqrt(2)

Solve for x: |x^2+x+1|=|2x^2+x-1|

The solution is x=-sqrt(2)\lor x=-2/3 \lor x=0\lor x=sqrt(2)

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x^{2} + x + 1 = 2 x^{2} + x - 1

x = - 2 or x = - \frac{2}{3} or x = 0 or x = 2

Decimal Notation

x = - 1.41421 \dots, x = - 0.66666 \dots, x = 0, x = 1.41421 \dots

Solution steps

x^{2} + x + 1 = 2 x^{2} + x - 1

Find positive and negative intervals

x \leq - 1, - 1 < x < \frac{1}{2}, x \geq \frac{1}{2}

Solve the inequality for each interval

x = - 2 or (x = - \frac{2}{3} or x = 0) or x = 2

x = - 2 or x = - \frac{2}{3} or x = 0 or x = 2

∣ 11 x + 22 ∣ + ∣ 3 x - 1 ∣ = 6 x + 6

x^{2} - 3 \cdot x ∣ 2 ∣ = x^{2} - 2 x

2 ∣ x + 1 ∣ + ∣ x - 2 ∣ = 5

y, ∣ y - 1 ∣ = x

∣ 2 x - 3 ∣ + ∣ x + 2 ∣ = 4

What is the answer to |x^2+x+1|=|2x^2+x-1| ?
The answer to |x^2+x+1|=|2x^2+x-1| is x=-sqrt(2)\lor x=-2/3 \lor x=0\lor x=sqrt(2)
Solve for x: |x^2+x+1|=|2x^2+x-1|
The solution is x=-sqrt(2)\lor x=-2/3 \lor x=0\lor x=sqrt(2)