What is the answer to solvefor x,ln|x|+v+ln|v-1|=ln|c| ?

The answer to solvefor x,ln|x|+v+ln|v-1|=ln|c| is No Solution for x\in\mathbb{R}

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solvefor x,ln|x|+v+ln|v-1|=ln|c|

solve for

x, ln ∣ x ∣ + v + ln ∣ v - 1 ∣ = ln ∣ c ∣

No Solution for x \in R

Solution steps

ln ∣ x ∣ + v + ln ∣ v - 1 ∣ = ln ∣ c ∣

Move

v

to the right side

ln ∣ x ∣ + ln ∣ v - 1 ∣ = ln ∣ c ∣ - v

Move

ln ∣ v - 1 ∣

to the right side

ln ∣ x ∣ = ln ∣ c ∣ - v - ln ∣ v - 1 ∣

Apply log rules

∣ x ∣ = \frac{e ^{- v} ∣ c ∣}{∣ v - 1 ∣}

Solve

∣ x ∣ = \frac{e ^{- v} ∣ c ∣}{∣ v - 1 ∣} :

No Solution for

x \in R

No Solution for x \in R

6 + lo g_{3} (5 x) = 8

lo g_{10} (4 x - 7) = lo g_{10} (x + 8)

lo g_{10} (x^{2}) = lo g_{10} (x)

lo g_{10} (a (a + 3)) = 1

lo g_{3} (2 x + 1) = 2

What is the answer to solvefor x,ln|x|+v+ln|v-1|=ln|c| ?
The answer to solvefor x,ln|x|+v+ln|v-1|=ln|c| is No Solution for x\in\mathbb{R}