What is the answer to ln(x-a)+ln(x)=1 ?

The answer to ln(x-a)+ln(x)=1 is x=(a+sqrt(a^2+4e))/2 ,x=(a-sqrt(a^2+4e))/2 {No Solution}

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ln(x-a)+ln(x)=1

ln (x - a) + ln (x) = 1

x = \frac{a + a ^{2} + 4 e}{2}, x = \frac{a - a ^{2} + 4 e}{2} {No Solution}

Solution steps

ln (x - a) + ln (x) = 1

Apply log rules

(x - a) x = e

Solve

(x - a) x = e : x = \frac{a + a ^{2} + 4 e}{2}, x = \frac{a - a ^{2} + 4 e}{2}

x = \frac{a + a ^{2} + 4 e}{2}, x = \frac{a - a ^{2} + 4 e}{2}

Verify Solutions:

x = \frac{a + a ^{2} + 4 e}{2}

True

, x = \frac{a - a ^{2} + 4 e}{2} {No Solution}

The solutions are

x = \frac{a + a ^{2} + 4 e}{2}, x = \frac{a - a ^{2} + 4 e}{2} {No Solution}

ln (7 x) = - 2

lo g_{10} (x - 4) = 2

lo g_{10} (10 x) = - 2

lo g_{10} (x) = 1 + lo g_{10} (22 - x)

2 lo g_{10} (x) = \frac{3 + lo g _{10} ( x )}{10}

What is the answer to ln(x-a)+ln(x)=1 ?
The answer to ln(x-a)+ln(x)=1 is x=(a+sqrt(a^2+4e))/2 ,x=(a-sqrt(a^2+4e))/2 {No Solution}