What is the answer to solvefor a,log_{2}(a)-3log_{2}(b)=2 ?

The answer to solvefor a,log_{2}(a)-3log_{2}(b)=2 is a=4b^3 {b>0}

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solvefor a,log_{2}(a)-3log_{2}(b)=2

solve for

a, lo g_{2} (a) - 3 lo g_{2} (b) = 2

a = 4 b^{3} {b > 0}

Solution steps

lo g_{2} (a) - 3 lo g_{2} (b) = 2

Move

3 lo g_{2} (b)

to the right side

lo g_{2} (a) = 2 + 3 lo g_{2} (b)

Apply log rules

a = 4 b^{3}

Verify Solutions:

a = 4 b^{3} {b > 0}

The solution is

a = 4 b^{3} {b > 0}

lo g_{3} (2 x + 3) = 5

lo g_{2} (x - 2) + lo g_{2} (x + 1) = 2

ln^{2} (x) = (ln (x))^{2}

lo g_{5} (x) = 520 - lo g_{54} (x)

7 ln (3 x) + 1 = 3

What is the answer to solvefor a,log_{2}(a)-3log_{2}(b)=2 ?
The answer to solvefor a,log_{2}(a)-3log_{2}(b)=2 is a=4b^3 {b>0}