What is the answer to log_{x}(7x-12)=2 ?

The answer to log_{x}(7x-12)=2 is x=4,x=3

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log_{x}(7x-12)=2

lo g_{x} (7 x - 12) = 2

x = 4, x = 3

Solution steps

lo g_{x} (7 x - 12) = 2

Apply log rules

\frac{ln ( 7 x - 12 )}{ln ( x )} = 2

Multiply both sides by

ln (x)

\frac{ln ( 7 x - 12 )}{ln ( x )} ln (x) = 2 ln (x)

Simplify

ln (7 x - 12) = 2 ln (x)

Apply log rules

7 x - 12 = x^{2}

Solve

7 x - 12 = x^{2} : x = 4, x = 3

x = 4, x = 3

Verify Solutions:

x = 4

True

, x = 3

True

The solutions are

x = 4, x = 3

2 lo g_{10} (x) - 2 lo g_{10} (x + 1) = 0

lo g_{2} (x) = - 5

(lo g_{2} (x)) 2 - 5 lo g_{2} (x) - 24 = 0

2 = lo g_{10} (x)

lo g_{10} (x) + lo g_{10} (x + 3) = 1

What is the answer to log_{x}(7x-12)=2 ?
The answer to log_{x}(7x-12)=2 is x=4,x=3
Solve for x: log_{x}(7x-12)=2
The solution is x=4,x=3