What is the answer to log_{3}(2x+1)+log_{3}(x+8)=3 ?

The answer to log_{3}(2x+1)+log_{3}(x+8)=3 is x=1

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log_{3}(2x+1)+log_{3}(x+8)=3

lo g_{3} (2 x + 1) + lo g_{3} (x + 8) = 3

x = 1

Solution steps

lo g_{3} (2 x + 1) + lo g_{3} (x + 8) = 3

Apply log rules

(2 x + 1) (x + 8) = 27

Solve

(2 x + 1) (x + 8) = 27 : x = 1, x = - \frac{19}{2}

x = 1, x = - \frac{19}{2}

Verify Solutions:

x = 1

True

, x = - \frac{19}{2}

False

The solution is

x = 1

ln (x - 1) = 1

4 \cdot lo g_{10} (x) = 3 \cdot (- 0.6655)

b, 2 lo g_{10} (9 a) - 3 lo g_{3} (b) = 1

lo g_{4} (5 x - 1) = 3

lo g_{x} (25) + lo g_{x} (5) = \frac{1}{2}

What is the answer to log_{3}(2x+1)+log_{3}(x+8)=3 ?
The answer to log_{3}(2x+1)+log_{3}(x+8)=3 is x=1
Solve for x: log_{3}(2x+1)+log_{3}(x+8)=3
The solution is x=1