What is the answer to ln(p^2)=ln(10p)-3 ?

The answer to ln(p^2)=ln(10p)-3 is p=(10)/(e^3)

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ln(p^2)=ln(10p)-3

ln (p^{2}) = ln (10 p) - 3

p = \frac{10}{e ^{3}}

Decimal Notation

p = 0.49787 \dots

Solution steps

ln (p^{2}) = ln (10 p) - 3

Apply log rules

p = \frac{10}{e ^{3}}

Verify Solutions:

p = \frac{10}{e ^{3}}

True

The solution is

p = \frac{10}{e ^{3}}

\frac{x}{lo g _{10} ( x ) ( \frac{1}{32} )} = 5

lo g_{2} (x) = 5

lo g_{10} (x) + lo g_{10} (x + 3) = 3

lo g_{2} (lo g_{3} (x)) = 4

lo g_{3} (x - 1) = 0

What is the answer to ln(p^2)=ln(10p)-3 ?
The answer to ln(p^2)=ln(10p)-3 is p=(10)/(e^3)
Solve for p: ln(p^2)=ln(10p)-3
The solution is p=(10)/(e^3)