What is the answer to log_{10}(2x+3)=log_{10}(7) ?

The answer to log_{10}(2x+3)=log_{10}(7) is x=2

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log_{10}(2x+3)=log_{10}(7)

lo g_{10} (2 x + 3) = lo g_{10} (7)

x = 2

Solution steps

lo g_{10} (2 x + 3) = lo g_{10} (7)

Apply log rules

2 x + 3 = 7

Solve

2 x + 3 = 7 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

lo g_{2} (x + 4) - lo g_{2} (x) = 1

x^{2 \cdot l o g_{10} (x)} = 10 x^{2}

\frac{lo g _{2} ( x ) - 1}{2} = lo g_{2} (x)

lo g_{10} (x) + lo g_{10} (x + 1) = 2

lo g_{10} (2 x - 3) = 1

What is the answer to log_{10}(2x+3)=log_{10}(7) ?
The answer to log_{10}(2x+3)=log_{10}(7) is x=2
Solve for x: log_{10}(2x+3)=log_{10}(7)
The solution is x=2