What is the answer to log_{9}(x-5)+log_{9}(x+3)=1 ?

The answer to log_{9}(x-5)+log_{9}(x+3)=1 is x=6

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log_{9}(x-5)+log_{9}(x+3)=1

lo g_{9} (x - 5) + lo g_{9} (x + 3) = 1

x = 6

Solution steps

lo g_{9} (x - 5) + lo g_{9} (x + 3) = 1

Apply log rules

(x - 5) (x + 3) = 9

Solve

(x - 5) (x + 3) = 9 : x = 6, x = - 4

x = 6, x = - 4

Verify Solutions:

x = 6

True

, x = - 4

False

The solution is

x = 6

lo g_{a} (x) = \frac{1}{b \cdot lo g _{a} ( c )}

lo g_{2} (x + 5) = 3

lo g_{3} (3 x + 4) = 3

lo g_{3} (2 x + 5) = 4

lo g_{10} (x - 1) = lo g_{10} (x + 2)

What is the answer to log_{9}(x-5)+log_{9}(x+3)=1 ?
The answer to log_{9}(x-5)+log_{9}(x+3)=1 is x=6
Solve for x: log_{9}(x-5)+log_{9}(x+3)=1
The solution is x=6