What is the answer to log_{10}(x^2)= 1/2 ?

The answer to log_{10}(x^2)= 1/2 is x=sqrt(\sqrt{10)},x=-sqrt(\sqrt{10)}

Solve for x: log_{10}(x^2)= 1/2

The solution is x=sqrt(\sqrt{10)},x=-sqrt(\sqrt{10)}

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lo g_{10} (x^{2}) = \frac{1}{2}

x = 10, x = - 10

Decimal Notation

x = 1.77827 \dots, x = - 1.77827 \dots

Solution steps

lo g_{10} (x^{2}) = \frac{1}{2}

Apply log rules

x^{2} = 10

Solve

x^{2} = 10 : x = 10, x = - 10

x = 10, x = - 10

lo g_{3} (4 x - 3) = 2

lo g_{3} (2 x - 5) = 1

lo g_{2} (x + 2) - lo g_{2} (3 x - 1) = - 1

ln (x) = - 2

lo g_{10} (4 x + 5) = 1 + lo g_{10} (x - 1)

What is the answer to log_{10}(x^2)= 1/2 ?
The answer to log_{10}(x^2)= 1/2 is x=sqrt(\sqrt{10)},x=-sqrt(\sqrt{10)}
Solve for x: log_{10}(x^2)= 1/2
The solution is x=sqrt(\sqrt{10)},x=-sqrt(\sqrt{10)}