What is the answer to log_{2}(8x-26)+log_{2}(4x-20)=2 ?

The answer to log_{2}(8x-26)+log_{2}(4x-20)=2 is x=(33+sqrt(57))/8

Solve for x: log_{2}(8x-26)+log_{2}(4x-20)=2

The solution is x=(33+sqrt(57))/8

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lo g_{2} (8 x - 26) + lo g_{2} (4 x - 20) = 2

x = \frac{33 + 57}{8}

Decimal Notation

x = 5.06872 \dots

Solution steps

lo g_{2} (8 x - 26) + lo g_{2} (4 x - 20) = 2

Apply log rules

(8 x - 26) (4 x - 20) = 4

Solve

(8 x - 26) (4 x - 20) = 4 : x = \frac{33 + 57}{8}, x = \frac{33 - 57}{8}

x = \frac{33 + 57}{8}, x = \frac{33 - 57}{8}

Verify Solutions:

x = \frac{33 + 57}{8}

True

, x = \frac{33 - 57}{8}

False

The solution is

x = \frac{33 + 57}{8}

3 = lo g_{10} (x) 125

lo g_{3} (x) = \frac{- 3}{2}

lo g_{25} (2 x - 1) = \frac{1}{2}

lo g_{10} (x) = 4

ln (x - 1) = 4

What is the answer to log_{2}(8x-26)+log_{2}(4x-20)=2 ?
The answer to log_{2}(8x-26)+log_{2}(4x-20)=2 is x=(33+sqrt(57))/8
Solve for x: log_{2}(8x-26)+log_{2}(4x-20)=2
The solution is x=(33+sqrt(57))/8