What is the answer to (log_{10}(x))^2+log_{10}(x)=2 ?

The answer to (log_{10}(x))^2+log_{10}(x)=2 is x=10,x= 1/100

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(log_{10}(x))^2+log_{10}(x)=2

(lo g_{10} (x))^{2} + lo g_{10} (x) = 2

x = 10, x = \frac{1}{100}

Decimal Notation

x = 10, x = 0.01

Solution steps

(lo g_{10} (x))^{2} + lo g_{10} (x) = 2

Rewrite the equation with

lo g_{10} (x) = u

(u)^{2} + u = 2

Solve

u^{2} + u = 2 : u = 1, u = - 2

u = 1, u = - 2

Substitute back

u = lo g_{10} (x),

solve for

x

Solve

lo g_{10} (x) = 1 : x = 10

Solve

lo g_{10} (x) = - 2 : x = \frac{1}{100}

x = 10, x = \frac{1}{100}

Verify Solutions:

x = 10

True

, x = \frac{1}{100}

True

The solutions are

x = 10, x = \frac{1}{100}

lo g_{7} (x^{2} - 9) = 1

ln (y) = 5

lo g_{2} (6) + 3 \cdot lo g_{2} (p) = 3

(x) = 50 + 8 lo g_{10} (14 + 3 x)

lo g_{2} (3 x - 7) = 3

What is the answer to (log_{10}(x))^2+log_{10}(x)=2 ?
The answer to (log_{10}(x))^2+log_{10}(x)=2 is x=10,x= 1/100
Solve for x: (log_{10}(x))^2+log_{10}(x)=2
The solution is x=10,x= 1/100