What is the answer to 2*log_{3}(x)-log_{3}(x+6)+1=2 ?

The answer to 2*log_{3}(x)-log_{3}(x+6)+1=2 is x=6

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2*log_{3}(x)-log_{3}(x+6)+1=2

2 \cdot lo g_{3} (x) - lo g_{3} (x + 6) + 1 = 2

x = 6

Solution steps

2 lo g_{3} (x) - lo g_{3} (x + 6) + 1 = 2

Apply log rules

x^{2} \cdot 3 = 9 (x + 6)

Solve

x^{2} \cdot 3 = 9 (x + 6) : x = 6, x = - 3

x = 6, x = - 3

Verify Solutions:

x = 6

True

, x = - 3

False

The solution is

x = 6

lo g_{2} (x) = 0

lo g_{2} (x) = 2

lo g_{2} (x) = 6

lo g_{10} (16 - x^{2}) - lo g_{10} (3 x - 4) = 2

lo g_{10} (x^{2} + 3) = lo g_{10} (x + 6)

What is the answer to 2*log_{3}(x)-log_{3}(x+6)+1=2 ?
The answer to 2*log_{3}(x)-log_{3}(x+6)+1=2 is x=6
Solve for x: 2*log_{3}(x)-log_{3}(x+6)+1=2
The solution is x=6