What is the answer to (log_{5}(x)-4)/(log_{5)(x)+3}=0 ?

The answer to (log_{5}(x)-4)/(log_{5)(x)+3}=0 is x=625

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(log_{5}(x)-4)/(log_{5)(x)+3}=0

\frac{lo g _{5} ( x ) - 4}{lo g _{5} ( x ) + 3} = 0

x = 625

Solution steps

\frac{lo g _{5} ( x ) - 4}{lo g _{5} ( x ) + 3} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

lo g_{5} (x) - 4 = 0

Move

4

to the right side

lo g_{5} (x) = 4

Apply log rules

x = 625

Verify Solutions:

x = 625

True

The solution is

x = 625

lo g_{2} (x^{2} - 4) + 1 = lo g_{2} (2 - x)

lo g_{4} (2^{x} + 48) = x - 1

lo g_{4} (x^{2} + 3 x - 1) = lo g_{4} (5 x - 1)

lo g_{x} (126) = 3

ln (2 x) = ln (x + 2)

What is the answer to (log_{5}(x)-4)/(log_{5)(x)+3}=0 ?
The answer to (log_{5}(x)-4)/(log_{5)(x)+3}=0 is x=625
Solve for x: (log_{5}(x)-4)/(log_{5)(x)+3}=0
The solution is x=625