What is the answer to log_{2}((x+4)^2)=4 ?

The answer to log_{2}((x+4)^2)=4 is x=0,x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}((x+4)^2)=4

lo g_{2} ((x + 4)^{2}) = 4

x = 0, x = - 8

Solution steps

lo g_{2} ((x + 4)^{2}) = 4

Apply log rules

(x + 4)^{2} = 16

Solve

(x + 4)^{2} = 16 : x = 0, x = - 8

x = 0, x = - 8

1 + lo g_{10} (x) = lo g_{10} (x + 1)

ln (x - 2) + ln (x + 2) = ln (3 x)

lo g_{9} (x + 1) - lo g_{9} (1 - x) = lo g_{9} (2 x + 3)

u, ln (1 - u) = x

ln (ln (x)) = 1

What is the answer to log_{2}((x+4)^2)=4 ?
The answer to log_{2}((x+4)^2)=4 is x=0,x=-8
Solve for x: log_{2}((x+4)^2)=4
The solution is x=0,x=-8