What are the solutions to the equation x^2-12x+10=0 ?

The solutions to the equation x^2-12x+10=0 are x=6+sqrt(26),x=6-sqrt(26)

Find the zeros of x^2-12x+10=0

The zeros of x^2-12x+10=0 are x=6+sqrt(26),x=6-sqrt(26)

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x^{2} - 12 x + 10 = 0

x = 6 + 26, x = 6 - 26

Solution steps

x^{2} - 12 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 10 = 226

x_{1, 2} = \frac{- ( - 12 ) \pm 2 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 26}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 26}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 26}{2 \cdot 1} : 6 + 26

x = \frac{- ( - 12 ) - 2 26}{2 \cdot 1} : 6 - 26

The solutions to the quadratic equation are:

x = 6 + 26, x = 6 - 26

x^{2} + 3 x + 8 \leq 0

x^{2} + x + 9 = 0

25 x^{2} - 60 x + 36

- 10 (- 3 d + 2) = 730

(1.5 x)^{2}

What are the solutions to the equation x^2-12x+10=0 ?
The solutions to the equation x^2-12x+10=0 are x=6+sqrt(26),x=6-sqrt(26)
Find the zeros of x^2-12x+10=0
The zeros of x^2-12x+10=0 are x=6+sqrt(26),x=6-sqrt(26)