What is the answer to solvefor y,x=2+ln(y+3) ?

The answer to solvefor y,x=2+ln(y+3) is y=e^{x-2}-3

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solvefor y,x=2+ln(y+3)

solve for

y, x = 2 + ln (y + 3)

y = e^{x - 2} - 3

Solution steps

x = 2 + ln (y + 3)

Switch sides

2 + ln (y + 3) = x

Move

2

to the right side

ln (y + 3) = x - 2

Apply log rules

y + 3 = e^{x - 2}

Solve

y + 3 = e^{x - 2} : y = e^{x - 2} - 3

y = e^{x - 2} - 3

Verify Solutions:

y = e^{x - 2} - 3

True

The solution is

y = e^{x - 2} - 3

2 lo g_{10} (x) - lo g_{10} (3) + x = 0

1 + lo g_{5} (x^{2} + 1) = lo g_{5} (x^{2} + 4 x + 1)

x, 2 lo g_{4} (x) - lo g_{2} (y) = 3

ln (2 x - 2) = 0

ln (2 x - 2) = 2

What is the answer to solvefor y,x=2+ln(y+3) ?
The answer to solvefor y,x=2+ln(y+3) is y=e^{x-2}-3