What is the answer to log_{2}(x)+log_{2}(x-2)=3 ?

The answer to log_{2}(x)+log_{2}(x-2)=3 is x=4

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log_{2}(x)+log_{2}(x-2)=3

lo g_{2} (x) + lo g_{2} (x - 2) = 3

x = 4

Solution steps

lo g_{2} (x) + lo g_{2} (x - 2) = 3

Apply log rules

x (x - 2) = 8

Solve

x (x - 2) = 8 : x = 4, x = - 2

x = 4, x = - 2

Verify Solutions:

x = 4

True

, x = - 2

False

The solution is

x = 4

lo g_{3} (x^{2} - 2 x + 1) = lo g_{3} (x^{2} + x + 7)

x, ln (\frac{x}{y}) = 3

13 lo g_{10} (10 x) = 338 - x lo g_{10} (10)

2 \cdot lo g_{2} (x) = 4

lo g_{2} (lo g_{3} (lo g_{3} (b))) = 0

What is the answer to log_{2}(x)+log_{2}(x-2)=3 ?
The answer to log_{2}(x)+log_{2}(x-2)=3 is x=4
Solve for x: log_{2}(x)+log_{2}(x-2)=3
The solution is x=4