What is the answer to log_{2}(x-2)+log_{2}(x-3)=1 ?

The answer to log_{2}(x-2)+log_{2}(x-3)=1 is x=4

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log_{2}(x-2)+log_{2}(x-3)=1

lo g_{2} (x - 2) + lo g_{2} (x - 3) = 1

x = 4

Solution steps

lo g_{2} (x - 2) + lo g_{2} (x - 3) = 1

Apply log rules

(x - 2) (x - 3) = 2

Solve

(x - 2) (x - 3) = 2 : x = 4, x = 1

x = 4, x = 1

Verify Solutions:

x = 4

True

, x = 1

False

The solution is

x = 4

lo g_{10} (10 a) = 4

0.868 x - 2.3 ln (x) = 1.195

lo g_{3} (2 - 3 x) = lo g_{9} (6 x^{2} - 19 x + 2)

5 = lo g_{10} (x)

lo g_{10} (3 x + 5) + 1 = lo g_{10} (2 x + 1)

What is the answer to log_{2}(x-2)+log_{2}(x-3)=1 ?
The answer to log_{2}(x-2)+log_{2}(x-3)=1 is x=4
Solve for x: log_{2}(x-2)+log_{2}(x-3)=1
The solution is x=4