What is the answer to solvefor x,(b)*y=ln(x^2) ?

The answer to solvefor x,(b)*y=ln(x^2) is x=sqrt(e^{by)},x=-sqrt(e^{by)}

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solvefor x,(b)*y=ln(x^2)

solve for

x, (b) \cdot y = ln (x^{2})

x = e^{b y}, x = - e^{b y}

Solution steps

(b) y = ln (x^{2})

Apply log rules

e^{b y} = x^{2}

Solve

e^{b y} = x^{2} : x = e^{b y}, x = - e^{b y}

x = e^{b y}, x = - e^{b y}

n = lo g_{10} (d) 150012

(lo g_{10} (x))^{2} - lo g_{10} (x) - 2 = 0

lo g_{2} (x - 1) = - 2022

(lo g_{2} (x))^{2} - 5 \cdot lo g_{2} (x) + 6 = 0

lo g_{10} (a) = 6

What is the answer to solvefor x,(b)*y=ln(x^2) ?
The answer to solvefor x,(b)*y=ln(x^2) is x=sqrt(e^{by)},x=-sqrt(e^{by)}